Question 1
Question
Answer
const numbers = [1, 2, 3, 4, 5]; const evenNumbers = numbers.filter(number => number % 2 === 0); console.log(evenNumbers); // Output: [2, 4]
const numbers = [1, 2, 3, 4, 5]; const sum = numbers.reduce((accumulator, currentValue) => accumulator + currentValue, 0); console.log(sum); // Output: 15
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